
Niral P. answered 06/06/20
Synthetic Chemist With 7+ Years Teaching Experience
Hi Andrea!
Looks like we have a lab-style question on our hands! For a question like this, there's a few things that we're going to need -- particularly some physical properties of the reagents we're using. These all came from the Sigma-Aldrich website.
p-anisaldehyde: (abbrev. p-A)
density: 1.119 g/mL
MW: 136.15 g/mol
p-methoxystilbene: (abbrev p-MS)
MW: 210.27 g/mol
So in order to calculate a theoretical yield, we would have to do so by starting with the limiting reagent, the p-anisaldehyde, and work our way to the final amount of p-methoxystilbene we could produce. So let's start with the .500mL and work our way to the end!
0.500 mL p-A * (1.119 g p-A / 1 mL p-A) * (1 mol p-A / 136.15 g p-A) * (1 mol p-MS / 1 mol p-A) * (210.27 g p-MS / 1 mol p-MS) = g p-MS (theoretical)
Which works out to be...0.864g p-methoxystilbene, theoretically.
Finally, we get to do a simple calculation for yield!
% Yield = (Actual yield / theoretical yield) * 100
% Yield = (0.573 g p-MS / 0.864 g p-MS) * 100 = 66.3% yield
Not great, but good enough! Hope that helps!
Niral