Sarah C. answered 06/06/20
Food Chemistry Researcher, Teaching Associate, Chemistry Tutor 3+ year
Specific heat of aluminum is 0.9 J/(g* K)
We can use q=m*c* ΔT or q=m*c*(Tf - Ti)
21.1 oC=294.1 K
Plugging everything in, 164 J = 11.6g (0.9 J/g*K) (Tf -294.1 K)
Distribute the right side of the equation and solve for Tf . Convert back to oC by subtracting 273 from K.