Find the vertices of the ellipse centered at the origin with eccentricity e=1/3 and foci at (0,−2) and (0,2)

Answer 1

Eccentricity e = c/a, by condition c = 2, then a = c/e = 2/(1/3) = 6. Then vertices of ellypse: (0, 6) and (0,- 6).

b² = a² - c² = 36 - 4 = 32. So b = 4sqrt2 and minor vertices of ellypse: (4sqrt2, 0) and (- 4sqrt2, 0)