Proportion of people with a certain genetic mutation is a binomial random variable.
The standard deviation of a binomial random variable is
Square Root of (n*p*(1-p)) = sqrt(900*.01*.99) = 3.0
Matthew R.
asked 06/03/20About 1% of the population has a particular genetic mutation. 900 people are randomly selected.
Find the standard deviation for the number of people with the genetic mutation in such groups of 900. (If possible, round to 1 decimal place.)
Proportion of people with a certain genetic mutation is a binomial random variable.
The standard deviation of a binomial random variable is
Square Root of (n*p*(1-p)) = sqrt(900*.01*.99) = 3.0
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