What volume (mL) of 1.50 × 10-2 M hydrochloric acid can be neutralized with 115 mL of 0.244 M sodium hydroxide?

Question

1.     What volume (mL) of 1.50 × 10^-2 M hydrochloric acid can be neutralized with 115 mL of 0.244 M sodium hydroxide?

Show your work, and include units throughout the solution

Answer 1

You need to first determine the number of moles of NaOH. You do this by multiplying the concentration of NaOH by its volume in liters. So...

0.244M * 0.115L = 0.02806mol NaOH

Since there is a 1-to-1 reaction between NaOH and HCl, you will need 0.02806 mol of HCL to react fully with NaOH. To determine the volume of HCl needed, you divide the moles you need by the concentration of the HCL solution, which gives...

0.02806mol/0.01500M = 1.87L

Then convert this number to mL by multiplying by 1000