Write the standard form equation of the parabola that passes through (−24,12), if the vertex at the origin and the axis of symmetry is horizontal.

Answer 1

WE have horizontal parabola y² = 4px. To get p we using point (-24,12), so 12² = 4p·(- 24), p = -144/96 = - 4/3.

Equation of parabola: y² = - 16/3x