I need help with this combined gas law problem

Question

If a gas has a volume of 3.2L at 25°C, what temperature in degrees C is needed to get a volume of 6.8 L

Answer 1

First, convert T₁ from Celsius to Kelvin:

T₁ = 25 °C + 273 = 298 K

Using the combined gas law:

P₁V₁ / T₁ = P₂V₂ / T₂

Assuming pressure is constant, this simplifies to:

V₁ / T₁ = V₂ / T₂

Solve for T₂ and then plug in values for V₁, V₂, and T₁:

T₂ = T₁V₂ / V₁ = (298 K) (6.8 L) / (3.2 L) = 633.25 K

Finally, convert T₂ from Kelvin to Celsius:

T₂ = 633.25 K - 273 = 360.25 °C