3 CO + Fe2O3 --> 2 Fe + 3 CO2 If 25.0 g of CO reacts how many grams of Fe is produced? If the same 25.0 g of CO reacts how many liters of CO2 is produced?

Answer 1

3 CO + Fe2O3 --> 2 Fe + 3 CO2

3 : 1 : 2 : 3

First calculate how many moles of CO there are in 25 g, using n=m/Mr

n = 25 g / 28.01 g/mol = 0.893 moles.

The mole ratio of CO : Fe is 3:2 =

So( 0.893/3)*2 moles of Fe will be produced in this reaction = 5.95E-1

mass = number of moles x molecular weight (Fe)

mass = 5.95E-1 x 55.845 g/mol

mass = 33.25g Fe

The mole ratio of CO : CO2 is 3:3 = 1:1

So 0.893 moles of CO2 will also be produced in this reaction.

One mole of an ideal gas at STP (Standard conditions of Temperature and Pressure = 1 atm, 273K) occupies one standard molar volume = 22.4 L

So the volume of CO2 produced is 0.893 moles * 22.4 L = 19.99 L