Calculate the new temperature when 2.00 L at 20.0°C is compressed to 1.00 L.

Answer 1

The question doesn't mentioned any pressures, so we can assume that it is constant (although the worrding may imply otherwise: "compressed").

We can use the combined gas law, (P₁V₁)/T₁ = (P₂V₂)/T₂ and, since P is constant, it drops out of the equation. Rearranging the equation and solving for T₂ we have:

T₂ = (V₂T₁)/V₁ The temp in ^oC must be first converted to Kelvins: K = ^oC + 273 = 20 + 273 = 293 K

T₂ = (1.00 L)(273K)/(2.00 L) = 136.5 K = 137 K (as 3 sig figs)