(32.0 g O2)/(1 mol O2) (3 mol O2/2 mol H2O) (1 mol H2O/18.0 g H2O) (8.53 g H2O) = 22.75 = 22.8 g O2
Griffin C.
asked 05/20/20If you end up with 8.53 grams of H2O, how many grams of O2 did you consume in this reaction?
Reaction:
__ B2H6 + _3_ O2 → _2_ HBO2 + _2_ H2O
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