800 grams was the original amount.
five half lives and half life can be represented by 2 and we raise the 2 ^5 2^5 = 32 and I multiplied 25 x 32 and got 800 grams
Mallory P.
asked 05/18/20The remaining amount of a strontium -90 that has had 5 half- lives pass is 25.0 g. How much was present at the beginning? Round to the correct number of significant figures and use units (g)
800 grams was the original amount.
five half lives and half life can be represented by 2 and we raise the 2 ^5 2^5 = 32 and I multiplied 25 x 32 and got 800 grams
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