
Patrick B. answered 05/17/20
Math and computer tutor/teacher
a divides b is given.
then a* n = b for some integer n.
a divides c is given.
then a * m = c for some integer m
subtracting the equations:
a * n - a* m = b - c
a(n - m) = b - c <-- distributive
since n and m are integers, n - m is
also an integer by closure property
of integer division.
So then there is an integer t = n-m
a* t = b - c
therefore,
t = (b-c)/a
which means a divides b - c
for integer t