Determine the concentration of [OH–] ions in an aqueous solution where the pH = 5.22

Answer 1

There are a few equations we need to consider:

(1) pH + pOH = 14

(2) pOH = -log[OH]

Since we know that the pH is 5.22, we can find the pOH by using equation (1):

pOH = 14 - pH ∴ pOH = 14 - 5.22 ∴ pOH = 8.78

We can rearrange equation (2) to solve for [OH]. if we multiply each side by (-1) and then raise both sides to the power of 10, we get:

10^-pOH = [OH].

∴10^-8.78 = [OH]

∴[OH] = 1.66*10^-9