Stoichiomtry combustion of acetyleme

Question

many mole of carbon dioxide are produce from combustion of 5.80g of acetylene(c2h2)?

Answer 1

First, let's write the combustion equation for acetylene. Remember - combustion reactions produce CO₂ and H₂O by mixing the original reagent with O₂.

C₂H₂ + O₂ -> CO₂ + H₂O

We need to balance the equation so the number of carbon, hydrogen, and oxygen atoms are equivalent on both sides of the equation:

C₂H₂ + 7/2 O₂ -> 2 CO₂ + 3 H₂O

Per the balanced equation, we know that 26.04 g (the molar mass) of C₂H₂ will produce 2 moles of CO₂. We need to know how many moles of CO₂ is produced by using 5.80 grams of C₂H₂.

So:

28.05 g of C₂H₂ = 2 moles of CO₂

We need:

5.80 g of C₂H₂ = X moles of CO₂

Solve for X:

X = (5.80 g x 2 mols) / 28.05 grams

x = 0.41 moles of CO₂