
Yefim S. answered 05/09/20
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∫110f(x)dx ≈ (4 +8)/2·(3 - 1) + (8 + 6)/2·(4 - 3) + (6 + 10)/2·(6 - 4) + (10 + 10)/2·(7 - 6) + (10 + 12)/2·(9 - 7) + (12 + 16)/2·(10 - 9) = 12 + 7 + 16 + 10 + 22 + 14 = 81.
Answer: 81