Kira B.
asked 05/08/20Anyone understand chem?
Solve for the by electroplating via electrolysis for each of the following sets of conditions, and then rank the masses by magnitude from smallest largest.
Metal. Reduction half reaction
(Ag). Ag+(aq)+e- ——>Ag(s)
(Al). Al3+(aq)+3e- ——>Al(s)
(Cu). Cu2+(aq)+2e- ——>Cu(s)
(Fe). Fe2+(aq) +2e- ——> Fe(s)
(No). Ni2+(aq) + 2e- ——> Ni (s)
1 Expert Answer
Step 1: calculate the total charge that passed through the cell:
Charge (in Coulomb, or C) = current (in Ampere, or A) x time (in second)
Step 2: convert the total charge (in C) to total charge (in number of moles of electrons)
number of moles of electrons = total charge (in C) / (96,485 C/mole of e)
Step 3: calculate the number of mole of a certain metal would be deposited
number of moles of metal = number of moles of electrons / # electrons transferred
# electrons transferred: for Ag: 1, Al:3; Ni, Fe, and Cu, 2
Step 4: calculate the mass of the metal deposited
mass of metal = number of moles of metal x molar mass
Based on the information you provided,
Cu 0.163 g
Al 0.201 g
Fe 0.322 g
Ag 0.500 g
Ni 0.535 g
Yongmao S.
05/24/20
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Kira B.
(Ag at 8.12A for 55s) (Al at 20.5A for 105s) (Cu at 2.67A for 185) (Fe at 14.8A for 75s) (Ni at 25A for 70s) I just don’t know how to work the calculations05/08/20