Kira B.

asked • 05/08/20

Anyone understand chem?

Solve for the by electroplating via electrolysis for each of the following sets of conditions, and then rank the masses by magnitude from smallest largest.


Metal. Reduction half reaction

(Ag). Ag+(aq)+e- ——>Ag(s)

(Al). Al3+(aq)+3e- ——>Al(s)

(Cu). Cu2+(aq)+2e- ——>Cu(s)

(Fe). Fe2+(aq) +2e- ——> Fe(s)

(No). Ni2+(aq) + 2e- ——> Ni (s)

Kira B.

(Ag at 8.12A for 55s) (Al at 20.5A for 105s) (Cu at 2.67A for 185) (Fe at 14.8A for 75s) (Ni at 25A for 70s) I just don’t know how to work the calculations
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05/08/20

Yongmao S.

tutor
Hopefully this answer may not be too late. I don't quite understand what additional information you placed in the Comment meant. It would be more reasonable to have a constant current and a fixed time for all five electroplating processes; otherwise you have to calculate one by one.
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05/24/20

1 Expert Answer

By:

Yongmao S.

tutor
if the electroplating would be conducted with a constant current and a fixed time, which means the total moles of electron passed are the same, with different numbers of electron transferred, you will see an increasing order of mass 3+ < 2+ < 1+ Also among three 2+ charged metals, based on the molar mass, Fe at 56, Ni at 59 and Cu at 64, the overall order of increasing mass should be Al
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05/24/20

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