John M. answered • 05/07/20

Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online

x = v₀ · cosα · t is the horizontal distance the shot put travels

t = x / (v₀ · cosα)

= 40 / (35 · cos40)

= 1.492 seconds

Alyce S.

asked • 05/07/20A shot put is thrown upward with a velocity of 35 ft./sec/ at a height of 4 ft. and an angle of 40 degrees. How long will it take for the shot put to be a horizontal distance of 40 ft. from the person throwing it? Acceleration due to gravity is 32 ft./s^2. Round your answer to the nearest hundredth.

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John M. answered • 05/07/20

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Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online

x = v₀ · cosα · t is the horizontal distance the shot put travels

t = x / (v₀ · cosα)

= 40 / (35 · cos40)

= 1.492 seconds

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