Precalculus Question #2

Question

A shot put is thrown upward with a velocity of 35 ft./sec/ at a height of 4 ft. and an angle of 40 degrees. How long will it take for the shot put to be a horizontal distance of 40 ft. from the person throwing it? Acceleration due to gravity is 32 ft./s^2. Round your answer to the nearest hundredth.

Answer 1

x = v₀ · cosα · t is the horizontal distance the shot put travels

t = x / (v₀ · cosα)

 = 40 / (35 · cos40)

 = 1.492 seconds