Log base a where log base a 7=.6

Question

log_a(cubred root√7 where log_a7=.6

Thanks!

Answer 1

log_a = [cuberoot(7)] is the same as log_a = (7)^1/3 which is the same as 1/3log_a(7)

Since you are given that

log_a7 = 0.6, we can say that 1/3log_a(7) is the same as 1/3(0.6) and 1/3(0.6) = 0.2