If you perform the reaction starting with 150 grams of Lead (IV) Oxide, how many grams of Sodium Oxide will be produced?

Answer 1

1. Write the balanced chemical equation for the reaction between lead (IV) oxide and sodium to form sodium oxide and lead.
2. PbO₂ + 4 Na → 2 Na₂O + Pb
3. To find how many grams of Na₂O will be produced, you will need to know the limiting reactant first. But because the question does not provide the amount of Na given, we can assume the sample of PbO₂ is our limiting reactant.
4. Some additional information, necessary to solve the problem:
5. molar mass PbO₂: 239.1988 g/mol
6. molar mass Na₂O: 61.97894 g/mol
7. With this information, we can use dimensional analysis to find the amount of Na₂O produced given 150 grams of PbO₂.

150 g PbO₂ × 1 mol PbO₂ / 239.1988 g PbO₂ × 2 mol Na₂O / 1 mol PbO₂ × 61.97894 g Na₂O / 1 mol Na₂O ≅ 77.73 g Na₂O