Energy to Specific Heat

Question

1) In the laboratory a student finds that it takes 635 Joules to increase the temperature of 11.8 grams of liquid water from 21.1 to 35.0 degrees Celsius.

The specific heat of water calculated from her data is ____ J/g°C.

2) In the laboratory a student finds that it takes 73.5 Joules to increase the temperature of 10.4 grams of solid iron from 21.2 to 38.2 degrees Celsius.

The specific heat of iron calculated from her data is ____ J/g°C.

3) In the laboratory a student finds that it takes 107 Joules to increase the temperature of 13.1 grams of solid titanium from 20.2 to 36.8 degrees Celsius.

The specific heat of titanium calculated from her data is ____ J/g°C.

Answer 1

1) q = C_s x m x ΔT Use this formula, solve for C_s, and plug in the values.

C_s = q/m x ΔT

= 635J /(11.8g x (35ºC - 21,1ºC)) = 3.87 J/g°C

2 and 3 can be done the exact same way.