Haley W.

asked • 04/30/20

If 3.19 L of propane at 24°C and 74.1 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produced?

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John M. answered • 05/03/20

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PV = nRT T = 273.15 + 24 oC = 297.15 K


n = (PV)/(RT) = [(74.1 kPa) (3.19 L)] / [(8.314 kPa L/n K) (297.15 K)] = 2.57 x 10-2 mol

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John M.

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I hadn't fully read the question, so there's more. Also, the calculated result should be 0.0957 mol, not 0.0257. Sorry about that. The balanced equation shows that 3 moles of CO2 are produced per one mole of C3H8. So, 3 x (0.0957) = 0.287 mol of CO2
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05/03/20

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