i do not now how to solve this

Question

log_a3=0.477 and log_a5=0.699. use these values to evaluate log_a75.

Answer 1

log_a75 = log_a(5 * 5 * 3) or log_a5 +log_a5 + log_a3

we have the values of log_a5 and log_a3 , so we can just add them;

log_a3=0.477 and log_a5=0.699.

so log_a75 = log_a5 +log_a5 + log_a3

=0.699 +0.699 + 0.477 = your answer

i hope this helps!!

Answer 2

75 = 3•25

75 = 3•5²

log_a75 = log_a(3•5²)

log_a75 = log_a(3) + log_a(5²)

log_a75 = log_a(3) + 2log_a(5)

log_a75 = 0.477 + 2(0.699)

log_a75 = 0.477 + 1.398

log_a75 = 1.875

Answer 3

3= a^0.477

_{5= a}^0.699

_{(5/3)= a}^0.222

_{log (5/3) = 0.222 log a}

_{log a = 0.999 or 1 approximately}

_{log a}⁷⁵ _{= (log 75)/ (log a) = log 75/1 = 1.875}