Determine the equation of the line with a y-intercept of 6 and crosses through point (-3, 12)

Answer 1

Use the point-slope form to find the slope when the y-intercept and the point are given. Then use the slope and the given point to write the equation in slope-intercept form.

y - y₀ = m(x - x₀)

y - 12 = m(x + 3)

6 -12 = m(0 + 3)

-6 = 3m

m = -2

y - 12 = -2(x + 3)

y - 12 = -2x - 6

y = -2x + 6