Please help with Calculus

Question

For an object whose velocity in ft/sec is given by v(t) = -t² + 6, what is its displacement, in feet, on the interval t = 0 to t = 3 secs?

Options:

1. 9.000
2. -9.000
3. 10.596
4. -3.00

Answer 1

Displacement = ∫(-t² + 6)dt

0

= ³₀ [-t³/3 +6t] = -27/3 +18 = -9 +18 =9ft