Gas Law Chemistry

Question

At standard temperature, a gas has a volume of 337 mL. The temperature is then increased to 127◦C, and the pressure is held constant. What is the new volume?

Answer 1

V1 = 337mL

V2 = ?

T1 = 0C + 273 = 273K

T2 = 127C + 273 = 400K

Using Charles' Law

V1/T1 = V2/T2

V2 = (T2V1)/T1

V2 = (400 * 337) / 273

V2 = 494 mL