Gas Law Chemistry

Question

A sample of air has a volume of 105 mL at 59 ◦C. At what temperature will its volume be 45 mL at constant pressure?

Answer 1

We know that based on the ideal gas law equation, PV=nRT. Therefore, V/T=nR/P, since n, R, and P are constants. So we get V₁/T₁₌V₂/T_{2. , where V is in mL and T is in K. Now, you plug in the values with the right units and solve.}

_{105mL/(273.15+59)K=45mL/x ---multiply x on both sides}

_{[(105mL)x]/332.15K=45mL ---multiply both sides by 332.15K}

_{(105mL)x=14946.75mL*K ---divide both sides by 105mL}

_{x=142.35K --- convert from Kelvin to Celsius (if needed) K=273.15+C ---> 142.35=273.15+C ---> C=-130.8 C}

_{x=-130.8 C}

_{-130.8 degrees Celsius is the final answer}