General chemistry

Question

Calculate the boiling point of a solution of 570.0 g of ethylene glycol (C2H6O2) dissolved in 800.0 g of water. Kf = 1.86°C/m and Kb = 0.512°C/m. Use 100°C as the boiling point of water.

determine the freezing point depression

Answer 1

Great Day Mik!

Boiling point elevation equation. A colligative property depending on the amount of particles in a solution.

Delta T of solvent = Boiling point constant(given) ( Molality) Van t hoff factor(Number of particles in solution)

molality = moles of solute / Kg of solvent = 9.19 moles of C2H6O2 / .8 Kg of water = 11.5 mols/ Kg

Delta T = .512 C/m 11.5 mols/ Kg ( 1)

Van t hoff factor = 1because C2H6O2 remains intact and does not dissociate ; therefore only contributes one particle.

Boiling point of water increases 5.89 degrees C

Boiling point of solution as described= 100 c + 5.89 C = 105.89 C