Elias W. answered 04/24/20
Flexible high school tutor - College Sophmore
Freezing point depression
The formula we will use for freezing point depression is
Tfo - Tf = Kfmi
Where Tfo is the standard freezing point of the liquid, Tf is the new freezing point, Kf is the freezing point constant, m is the molality of the solution, and i is a constant that describes dissociation (called the Vant Hoff factor)
First, the Tfo of water is 0 oC. Then, we know that the given Kf is 1.86. Finally, as the solute (the molecule being dissolved) is a non-electrolyte, we can assume that i=1.
Now, all we need to do to solve this problem is find the molality (m) as we have all of the other variables. Molality is a ratio of moles of solute divided by kilograms of solvent.
First, we have to find how many moles of solute we have
50.7g solute 1 mol solute = 0.551 mol solute
92.09g solute
Next, we need to find how much our solvent weighs, in kilograms (the density of water is 1 gram per 1 mL)
376mL water 1g 1kg = 0.376 kg of solvent
1ml 1000g
Now molality
0.551 mol solute / 0.376 kg solvent = 1.47 molal
We now have all the variables needed to solve. So, plugging in the numbers
0 - Tf = (1.86)*(1.57)*(1)
-Tf = 2.92
Tf = -2.92 oC is the new freezing point
Boiling point elevation
The boiling point elevation equation is
Tb - Tbo = Kbmi
The variables here are similar to the freezing point equation, where Tb is the new boiling point, Tbo is the standard boiling point, Kb is the boiling point constant, m is molality, and i is the Vant hoff factor.
We know that Tbo = 100 oC, Kb = 0.512, m = 1.47 (from the previous calculation), and that i = 1
So, plugging in the values
Tb - 100 = (0.512)*(1.47)*(1)
Tb = 100 + 0.753
Tb = 100.753 0C is the new boiling point