calculate the mass of HCL that reacted with the Zn

Question

3g of Zn was made with 0.1 of HCL according to the equation Zn+2HCL-------ZnCL2+H2

Answer 1

A FUN stoichiometry problem! Making 2 assumptions:

unit on .1 is M for molarity and the density of the HCl solution is 1.0 g/cc ( only way to calculate this problem!

1) Moles of Zn = 3 g of Zn / 65.38 g / mole Zn = .0459 moles of Zn

2) Use balanced chemical equation with coefficients to calculate Moles of HCl required to react with Zn :

.0459 moles Zn ( 2 moles HCl / 1 mole Zn) = .0918 moles of HCl required to react with ,0459 moles of Zn.

3) Use molarity equation to calculate volume of HCl required Molarity = Moles/ liters

.1 M = .0918 moles / Liters Liters = .918 liters = 918 cc ( cubic centimeters)

4) convert volume to mass by using density equation: mass = D ( V) = 1.0 g/cc ( 918 cc) = 918 grams of .1 M solution required to react with 3 g of Zn.

Yours in chemistry Success!

Dale Swanson