
Thomas N. answered 04/22/20
MIT Mechanical Engineer for Math and Science Tutoring
40.9 g C * 1 mol C/12 g C = 3.4 mol C
4.58 g H * 1mol H/1.01 g H = 4.53 mol H
54.52 g O * 1 mol O/16 g O = 3.4 mol O
so we see the ratio of Carbon and Oxygen are the same. Now we need to determine ratio with Hydrogen.
4.53/3.4 = 1.33 so there are 1.33 molecules of H for every C and O which gives us CH1.33O but we need whole numbers so multiply everything by 3 getting C3H4O3 for empirical formula