In the following reaction; 2 Mg(s) + CO2(s)  2 MgO(s) + C(s), how many grams of MgO can be produced from 5.7 moles of Mg?

Answer 1

Use stoichiometry:

First find how many moles of MgO is produced from 5.7 moles of Mg:

We find the mole ratio of MgO to Mg by looking at the coefficients of the balanced equation 2Mg and 2MgO: Ratio = 2/2

5.7 moles Mg * 2 moles MgO/2moles Mg = 5.7 moles MgO produced

then convert moles of MgO to grams MgO using the molar mass of MgO is 40.3grams in a mole of MgO

5.7 moles MgO * 40.3 g MgO/1 mol MgO = 229.71 grams of MgO