Indicated probability

Question

Suppose that 14% of people are left handed. If 8 people are selected at random, what is the probability that exactly 2 of them are left handed?

Answer 1

P(left handed) is distributed as a binomial distribution assuming there are only two outcomes left and right handed, and 8 is less than 10% of the population of people.

P(X=2) = 8C2 * (0.14^2) * (0.86)^6 = 0.22

8C2 is read 8 choose 2 = 8!/(2!*6!)