
Lois C. answered 04/20/20
BA in secondary math ed with 20+ years of classroom experience
Hello Natalie. Given that cosine is positive but tangent is negative, the angle you're working with must be in the 4th quadrant ( per "All Students Take Calculus", if you're familiar with that memory aid!). So if we draw a diagram and set up a triangle in the 4th quadrant with a reference angle of "theta", we can then label the adjacent side of the triangle ( i.e. the side lying on the positive x-axis) as 15, and the hypotenuse of the right triangle as 17. By Pythagorean Theorem, we can determine that the side opposite angle "theta" ( i.e. the vertical side going down from the x-axis) is 8 units in length.
Now we are ready to determine the ratios for the remaining 5 trig functions, keeping in mind which ratios will be positive in the 4th quadrant and which ones will be negative. So here we go:
sin = -8/17;
tan = -8/15;
cot = -15/8
sec = 17/15;
csc = -17/8