
Ethan T. answered 04/09/21
Senior at Cornell University
If you are looking for the critical points where f'(x) = 0, the answer is: x = 10,1.
To find critical points using Calculus, we set the derivative of the function, f'(x), to 0.
In this example, f'(x) is 6x^2-66x+60. We get this by using the Power Rule.
Next, we can factor out a 6 from this equation, and we get: 6(x^2-11x+10) = 0.
Now, we factor the x^2-11x+10 equation, which results in: (x-10)(x-1). Putting that back into our equation in the line above, we now have: 6(x-10)(x-1) = 0. Solving for x, we get x = 10 and 1.
Hope that helps!