How many children and how many adults were admitted?

Question

The admission fee at an amusement park is $3.50 for children and $6.80 for adults. On a certain day, 287 people entered the park, and the admission fees collected totaled 1582 dollars.

Answer 1

To begin you would want to set up two equations, setting x as your number of children and y as your number of adults.

x + y = 287

3.50x + 6.80y = 1582

From here, you would solve using substitution.

First, solve for x in the second equation ----> x = 287 - y

Then, substitute this in for x into the first equation ----> 3.50(287-y) + 6.80y = 1582

This leaves us with one variable in the equation, which we can now easily solve for!

1004.50 - 3.50y + 6.80y = 1582

Combine like terms and thus, y = 175

Then use the solved value of y and plug it into the original equation to find x.

x + y = 287 ---> so x + 175 = 287

x = 112

Don't forget to plug your answers back into the original equation to check if they are correct.

3.50(112) + 6.80(175) = 1582

Looks like it works! Hope this helps!