
Matthew S. answered 04/17/20
Ph in Operations Research with extensive background in probability
(A) Of the 919 students (total incl boys & girls), 96 are boys in year10. Assuming that each student has an equal chance of being selected, P(boy in Y10) = 96/919 ≈ .104. So, about 10%
(B) Of the 459 girls at the school, 88 are in year 8. Assuming that each girl has an equal chance of being selected, P(girl is in Y8) = 88/459 ≈ .192. So, about 19%