how many cm3 h2so4 1m solution will act with 16.8 g nahco3?

Question



Answer 1

A cm3 is a mL.

So how many mL do you need of a 1 M solution to react with 16.8 g of sodium bicarb?

The reaction is this:

H2SO4 + 2NaHCO3 --> Na2SO4 + 2H2O + 2CO2

Convert to moles:

(16.8 g NaHCO3/1)*(1 mole/84 g) = 0.20 moles bicarb

(0.20 moles bicarb/1)* (1 mole H2SO4/2 moles bicarb)*(1 L/1 mole H2SO4) = 0.10 L or 100 mL