
Peter M. answered 04/15/20
Experienced math tutor
cov(W,L) = p(10)(10-6)(0-3) + p(9)(9-6)(1-3)...p(0)(0-6)(10-3)
corr(W,L) = cov(W,L)/sigma(W)sigma(L)
sigma^2(W) = p(10)(10-6)^2 + p(9)(9-6)^2 + ... + p(0)(0-6)^2
similarly for sigma^2(L)
where p(n) is the binomial probability for n of 10
This is a lot of computation, but not too bad if you use a spreadsheet
Jacob B.
would the cov(W,L) be -310p then ?04/15/20