A sample of PH3 gas is 60.67 mL at 259.24 K. What will be the new temperature if the gas is compressed to 36.8 mL under constant pressure?

Answer 1

We will be using Charles Law: V_1/T₁ = V₂/T₂

We know the following:

V₁ = 60.67 mL V₂ = 38.8 mL

T₁ = 259.24 K T₂ = ?

Rearrange the equation to get T₂ by itself:

T₂ = V₂(T₁)(/V₁) = 38.8 mL(259.24 K ) = 165. 79 K

60.67 mL