A 4.76 mole sample of a gas at 4 atm is in a 12.5 L container. What is the temperature inside the container?

Answer 1

We would use the Ideal Gas Law: PV = nRT

Given our units, we will use 0.0821 L atm/mol K for the R constant.

We will list what we know and don't know:

P = 4 atm

V = 12.5 L

n = 4.76 mole

T = ?

Now solve for T

PV = nRT

T = PV/nR = 4 atm(12.5 L)/(4.76 mole) 0.0821 L atm/mol K = 127.9 K