What is original concentration of a solution that has a volume of 63 mL that is diluted to a concentration of 6.8 M of 100 mL?

Answer 1

Let's use our handy dandy equation, C₁V₁ = C₂V₂ , Where the left side is the original solution (C₁V₁), and the right is the dilution or working solution (C₂V₂). Note that concentration and volume are inversely related.

1. C₁ - original concentration
2. V₁ - original volume
3. C₂ - new concentration
4. V₂ - new volume

Plug it in, solving for original concentration (C₁):

1. C₁V₁ = C₂V₂
2. (C₁)(63mL) = (6.8M)(100mL)
3. (C₁) = (6.8M • 100mL) / (63mL)
4. C₁ = 10.8 M