
Patrick B. answered 04/18/20
Math and computer tutor/teacher
First, note that IF x-1 is the factor then x=1 is the solution;
f(1) = 1^2 +3(1) - 1 = 1 +3 - 1 = 3 so the remainder shall be 3;
As a result, x=1 is not a solution and x-1 is not a factor
x + 4
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x-1 | x^2 + 3x - 1
x^2 - x
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4x -1
4x - 4
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3
The quotient is x-1 and 3 is the remainder as expected
check step:
(x-1)(x+4) +3 = x^2 +3x - 4 +3 = x^2 +3x - 1