A container containing 4.29 L of a gas is collected at 89 K and then allowed to expand to 16 L. What must the new temperature be in order to maintain the same pressure

Answer 1

This is a Charles' Law problem. Charles' Law is V₁/T₁ = V₂/T₂

V1=4.29 L

T1= 89K

V2= 16L

T2=?

4.29 L /89K = 16L /X

Multiply both sides by X

X 4.29L /89 K = 16L

multiply both sides by 89K

X4.29L = 16L 89K

divide both sides by 4.29L

X= 16L 89K/4.29 L

V2= 331.93 L

If you have to consider significant figures, the answer should be expressed to two significant figures. So the answer should be 330 L ( I am omitting the period so it is not confused with 330. which has 3 significant figures)

This of course can be done by cross multiplication but I included all the algebra so you can see how it is done.