Chemistry Ideal gas law

Question

Calculate the pressure exerted by a

Answer 1

The ideal gas law is: PV = nRT (R=0.08206 L*atm/mol*K)

1) A reaction yields 0.00512 mol of O2 gas. What volume will the gas occupy if it is collected at 42.0◦C and 0.850 atm pressure?

n = 0.00512 mol O2

T = 42C+273K = 315K

P = 0.850atm

PV = nRT

(0.850atm)V=(0.00512 mol O2)(.08206 L*atm/mol*K)(315K)

0.85V=.1323

V=.1323/0.85

V=.156 L

2) Calculate the pressure exerted by a) 3.70 L of HF containing 2.35 mol at 350 K.

V=3.70L n=2.35mol T=350K

PV=nRT

P=(nRT)/V

P=(2.35mol)(.08206 L*atm/mol*K)(350K)/(3.70L)

P=18.2 atm

3) 3.90 L of NO2 containing 0.503 mol at 270 K.

V=3.90L n=0.503mol T=270K

P=(nRT)/V

P=[(0.503mol)(.08206 L*atm/mol*K)(270K)]/(3.90L)

P=2.86atm

4) 502 mL of CO2 containing 1.12 mol at 59.0◦C.

V=0.502L n=1.12mol T=273+59=332K

P=(nRT)/V

P=[(1.12mol)(.08206 L*atm/mol*K)(332K)]/(.502L)

P=60.8atm

5) A 7.87 L cylinder contains 1.61 mol of helium gas at 43◦C. What is the pressure of the gas in the cylinder?

V=7.87L n=1.61mol T=273+43=316K

P=(nRT)/V

P=[(1.61mol)(.08206 L*atm/mol*K)(316K)]/(7.87L)

P=5.30atm