If a 3.6 moles of an ideal gas occupies 150 mL tank at a temperature of -5 °C, what is the pressure inside the tank?

Answer 1

You will use PV= nRT

P = ?

V = 150 ml = o.150 L

n = 3.6 moles

R = 0.08206 L atm/mol K

T = -5 ºC

Let's convert Celsius to Kelvein:

-5 + 273 = 268 K

Now we substitute in the known values:

PV = nRT

P(0.150L) = 3.6 mol(0.08206 L atm/mol K) 268 K

P = 3.6 mol(0.08206 L atm/mol K) 268 K/ 0.150 L = 528 atm