molarity for a solution containing 0.500 L and 34.2 g of sucrose, C12H22O11.

Answer 1

Molarity = moles of solute / liters of solution

Molarity of sucrose solution = moles of sucrose / liters of solution

Moles of sucrose = grams of sucrose / molar mass of sucrose

(34.2 g sucrose / (342 g/1 mole) = 0.1 moles sucrose

Molarity of sucrose solution = moles of sucrose / liters of solution

0.1 moles sucrose / 0.500 L solution = 0.2 M sucrose solution