
Peter P. answered 04/05/20
Bachelors degree in science with years of tutoring experience
ΔGrxn = ΔGοrxn + RT ln K = (-48100J/mol) + (8.314J/mol K)(298K)(ln(11)) = -48100J +5940J = -42159J
=42.16kJ
K=1/[Ca2+][CO32-] = 1/[.356][.255]=11
Oscar A.
asked 04/05/20The value of ΔGo for the precipitation reaction,
Ca2+(aq) + CO32-(aq) <=> CaCO3(s)
is -48.1 kJ at 298 K.
Calculate the value of ΔG in kJ at 298 K if the concentrations of Ca2+(aq) and
CO32-(aq) are 0.356 and 0.255, M respectively.
My answer was -50.68 somehow
The correct answer is -42.16
Peter P. answered 04/05/20
Bachelors degree in science with years of tutoring experience
ΔGrxn = ΔGοrxn + RT ln K = (-48100J/mol) + (8.314J/mol K)(298K)(ln(11)) = -48100J +5940J = -42159J
=42.16kJ
K=1/[Ca2+][CO32-] = 1/[.356][.255]=11
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