chem hw help pls

Question

For the following reaction,  5.76 grams of  sulfur dioxide are mixed with excess  oxygen gas . The reaction yields  5.14 grams of  sulfur trioxide .

sulfur dioxide ( g ) +  oxygen ( g )   sulfur trioxide ( g )

What is the theoretical yield of sulfur trioxide?

What is the percent yield for this reaction ?

Answer 1

2SO₂(g)+O₂(g)--->2SO₃(g) balance equation

MW SO2 =48.06g/mol molecular weight of SO₂ is 32.06amu of S + 32.00amu of 2O

do same for SO₃

5.57gSO_{2 X} mol SO₂ /48.06g SO₂ x 2 mol SO₃ / mol SO₂ = .231 mol SO₃

.231 mol SO₃ x 80.12 g SO₃ / mol SO₃ = 18.5 g SO₃ theoretical yield of SO₃

5.14gSO₃ / 18.5g SO₃ x 100% = 27.8% percent yield = actual yield/theoretical yield

5.67gSO2