Melamine, C3N3(NH2)3, is used in adhesives and resins. It is manufactured in a two-step process:CO(NH2)2 (l) → HNCO (l) + NH3 (g) 6 HNCO (l) → C3N3(NH2)3 (l) + 3 CO2 (g)

Question

What mass of melamine will be obtained from 177.5 kg of urea, CO(NH₂)₂, if the yield of the overall reaction is 79.0%?

(question didn't fit)

Answer 1

Based on the equation the mole rations are 1:1 for this reactant : product.

Therefore you have to determine how many moles of Urea you started with, and it will be the same amount of moles of Melamine produced if the reaction wet to 100%. But your reaction only has a 79% yield, meaning you need to multiply the number of moles calculated by .79. If you need the answer in grams calculate molar mass of Melamine and convert from Moles to grams.

Urea has a Molar mass of about 60g/mol. You need to convert Kg to g in your initial sample to calculate. Simply meaning move the decimal three places to the right or multoply by 1000 to get 177500g Urea. Divide by 60 to get moles. Then multiply by .79 to yield moles of melamine and convert to grams if needed.