1.448 moles Ag:
Cu + 2Ag(NO3)2 = 2Ag + Cu(NO3)2
46g Cu / 63.54g/mole = 0.724 moles Cu
Since 1mole of Cu yields 2 moles of Ag,
2 * 0.724 moles = 1.448 moles Ag
Isabella C.
asked • 04/01/20how many moles of AG will be produced from 46 g of CU assuming AGNO3 is available in excess
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